In
an example discussed earlier we saw that the reaction of NO with H2
leads to a rate
expression that is different from what might be expected from
the equation of the reaction alone:
The reaction is first
order in H2
concentration, not second
order. One mechanism that will account for this rate behavior
is
This mechanism is illustrated in fig 7
opposite. If all reactions except the k3
process are quite fast, then the rate equation is
You should be able to use the first equilibrium
condition to eliminate N202
concentration, and show that the rate equation given previously
is the result.
The last reaction (k4)
occurs so fast that it scavenges any N20
as rapidly as it is formed, and has no effect on the overall rate
of the process. In effect, N2 is produced
as fast as N20 appears, so
In a series of reactions, the slowest
one has the greatest influence on reaction rates. To invoke a painful
analogy, if it takes ten days to to get a certified letter from
Los Angeles to the White House, then rushing to get it into the
one o'clock mail instead of the three o'clock will make little difference
in the long run.